# EXERCISE – 2.7

Q1. Find:

(i) 0.4 ÷2

SOLUTIONS:-

= 0.2

(ii) 0.35 ÷ 5

SOLUTION:-

= 0.07

(iii) 2.48 ÷ 4

SOLUTION:-

= 0.62

(iv) 65.4 ÷ 6

SOLUTION:-

= 80.4

(v) 651.2 ÷ 4

SOLUTION:-

= 0.35

(vi) 14.49 ÷ 7

SOLUTION:-

= 844.08

(vii) 3.96 ÷ 4

SOLUTION:-

= 1.72

(viii) 0.80 ÷ 5

SOLUTION:-

= 0.16

Q 2. Find:

(i) 4.8 ÷ 10

SOLUTION:-

= 0.48

(ii) 52.5 ÷ 10

SOLUTION:-

= 5.25

(iii) 0.7 ÷10

SOLUTION:-

= 0.07

(iv) 33.1 ÷ 10

SOLUTION:-

= 3.31

(v) 272.23 ÷ 10

SOLUTION:-

= 27.223

(vi) 0.56 ÷ 10

SOLUTION:-

= 0.056

(vii) 3.97 ÷ 10

SOLUTION:-

= 0.397

Q3. Find:

(i) 2.7 ÷ 100

SOLUTION:-

= 0.027

(ii) 0.3 ÷100

SOLUTION:-

= 0.003

(iv) 432.6 ÷100

SOLUTION:-

= 4.326

(v) 23.6 ÷ 100

SOLUTION:-

= 0.236

(vi) 98.53 ÷ 100

SOLUTION:-

= 0.9853

Q4. Find:

(i) 7.9 ÷1000

SOLUTION:-

=

0.0079

(ii) 26.3 ÷ 1000

SOLUTION:-

= 0.0263

(iii) 38.53 ÷ 1000

SOLUTION:-

= 0.03853

(iv) 128.9 ÷ 1000

SOLUTION:-

= 0.1289

(v) 0.5 ÷ 1000

SOLUTION:-

= 0.0005

Q5. Find:

(i) 7 ÷ 3.5

SOLUTION:-

= 2

(ii) 36 ÷ 0.2

SOLUTION:-

= 180

(iii) 3.25 ÷ 0.5

SOLUTION:-

= 6.5

(iv) 30.94 ÷ 0.7

SOLUTIOON:-

= 44.2

(v) 0.5 ÷ 0.25

SOLUTION:-

= 2

(vi) 7.75 ÷ 0.25

SOLUTION:-

= 31

(vii) 76.5 ÷ 0.15

SOLUTION:-

= 510

(viii) 37.8 ÷ 1.4

SOLUTION:-

= 27

(ix) 2.73 ÷ 1.3

SOLUTION:-

= 2.1

Q6. A vehicle covers a distance of 43.3 km in 2.4 liters of petrol . How much distance will it cover in liter of petrol ?

SOLUTION:-

From the question , it is the given that

Total distance covered by vehicle in 2.4 liters of petrol = 43.2 km

Then,

Distance covered in 1 liter of petrol = 43.2 ÷ 2.4

= (432/10) ÷(24/10)

= (432/10) x (10/24)

= (432x 10)/(10 x 24)

= (36 x 1) / (1 x 2)

= (18 x 1) /(1 x 1)

= 18 km

Total distance covered in 1 liter of petrol is 18 km.