# EXERCISE – 3.2

Q1. The scores in mathematics test ( out of 25) of 15 students is as follows:

19,25,23,20,9,20,15,10,5,16,25,20,24,12,20

Find the mode and median of this data. Are they same?

SOLUTION:-

Arranging the given scores in an ascending order, we get

5,9,10,12,15,16,19,20,20,20,20,23,24,25,25

Mode,

Mode is the value of the variable which occurs most frequently .

Clearly , 20 occurs maximum numbers of times.

Hence, mode of the given scores is 20

Median,

The value of the middle most observation is called the median of the data .

Here n = 15 , which is odd.

Where , n is the numbers of the

students.

median = value of ½ (n + 1 ) th observation.

= ½ (15+1)

= ½ (16)

= 16/2

= 8

Then, value of 8th term = 20

Hence, the median is 20.

Yes, both the values are same.

Q2. The runs scored in a cricket match by 11 players is as follows:

6,15,120,50,100,80,10,15,8,10,15,

Find the mean , mode and median of this data. Are the three same?

SOLUTION:-

Arranging the  runs scored in a cricket match by 11 players in an ascending order , we get

6,8,10,10,15,15,15,50,80,100,120

Mean,

Mean of the given data = Sum of all observations / Total numbers of observations

= ( 6+8+10+10+15+15+15+50+80+100+120+)/11

= 429/11

= 39

Mode = 15

Median,

Here n = 11, which is odd.

Where , n is the numbers of players.

median = value of ½ ( n + 1 )th observation.

= ½ ( 11+1)

= ½ (12)

= 12/2

= 6

Then, value of 6th term = 15

Hence, the median is 15.

No, these three are not same.

Q3. The weights ( in kg ) of 15 students of a class are:

38,42,35,37,45,45,50,32,43,43,40,36,38,43,38,47

(i) Find the mode and median of this data.

(ii) Is there more than one mode?

SOLUTION:-

Arranging the given weights 15 students of a class in an ascending order, we get

32,35,36,37,38,38,38,40,42,43,43,45,47,50

(i) Mode and median

Mode,

Mode = 38 , 43

Median,

Here n = 15 , which is odd

Where, n is the numbers of the students.

median = value of ½ ( n + 1 )th observation.

= ½ ( 15+1)

= ½ (16)

= 16/2

= 8

Then, value of 8th term = 40

Hence , the median is 40.

(ii) Yes, there are 2 modes for the given weights of the students.

Q4. Find the mode and median of the data: 13,16,12,14,19,12,14,13,14,

SOLUTION:-

Arranging the given data in an ascending order, we get

= 12,12,13,13,14,14,14,16,19

Mode,

Mode = 14

Median,

Here n = 9, which is odd.

Where, n is the numbers of the students .

median = value of ½ ( 9+ 1)th observation.

= ½ ( 9+ 1)

= ½ (10)

= 10/20

= 5

Then, value of 5th term = 14

Hence, the median is 14.

Q5. Tell whether the statement is true or false:

(i) The mode is always one of the numbers in a data.

(ii) The mean is one of the numbers in a data.

(iii) The median is always one of the numbers in data .

(iv) The data 6,4,3,8,9,12,13,9,has mean 9.

SOLUTION:-

(i) The statements is given above is true.

Because, Mode is the value of the variable which occuirs most frequently in the given data.

Hence, mode is always one of the numbers in a data .

(ii) The statements given above is false.

Because, mean is may be or may not be one of the numbers in a data.

(iii) The statements is given above s true.

Because, median is the value of the middle – most observation in the given data while arranged in ascending or descending order.

Hence, median is always one of the numbers in a data

(iv) Mean = Sum of all observations/numbers of observations

= (6+4+3+8+9+12+13+9)/8

= (64/8)

= 8

Hence, the given statements is false