NCERT Solutions For Class 10 Math Chapter – 3 Linear equation in two variables Exercise – 3.2
Q1. From the pair of linear equations in the following problems, and find their solutions graphically.
- 10 students of Class 10 took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
Solution:-
Let the number of boys = x
No of girls = y
Given that total number of student is 10 so that
X + y = 10
Subtract y both side we get
X = 10 – y
Putting y = 0 , 5 , 10 we get
X = 10 – 0
X = 10 – 5 = 5
X = 10 – 10 = 0
x | 10 | 5 |
y | 0 | 5 |
Given that if the number of girls is 4 more than the number of boys
So that
Y = x + 4
Putting x = -4 , 0 , 4 and we get
Y = -4 + 4 = 0
Y = 0 + 4 = 4
Y= 4 + 4 = 8
x | -4 | 0 | 4 |
y | 0 | 4 | 8 |
Graphical representation
Therefore , number of boys = 3 and number of girls = 7.
- 5 pencils and 7 pens together cost Rs 50 whereas 7 pencils and 5 pens together cost Rs 46 . Find the cost of one pencil and that of one pen.
Solution:-
5x + 7y = 50
5x = 50 – 7y
X = 10 – 7y/5
Putting value of y = 5 , 10 and 15 we get
X = 10 — 7 x 5/5 = 10 – 7 = 3
X = 10 – 7 x 10/5 = 10 – 14 = -4
X = 10 – 7 x 15/5 = 10 – 21 = 11
x | 3 | -4 | -11 |
y | 5 | 10 | 15 |
7x + 5y = 46
5y = 46 – 7x
Y= 9.2 – 1.4x
Putting x = 0.2 and 4 we get
Y = 9.2 – 1.4 x 0 = 9.2
Y = 9.2 – 1.4 x 2 = 6.4
Y = 9.2 – 1.4 (4) = 3.6
x | 0 | 2 | 4 |
y | 9.2 | 6.4 | 3.6 |
Graphical representation
Therefore , cost of one pencil = Rs 3 and cost of cost of one pen = Rs 5.
Q2. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident.
Solution:-
- 5x – 4y + 8 = 0
7x + 6y – 9 = 0
Therefore , both are intersecting lines at one point.
- 9x + 3y + 12 = 0
18x + 6y + 24 = 0
Therefore , both lines are coincident.
- 6x – 3y + 10 = 0
2x – y + 9 = 0
Therefore , both lines are parallel.
Q3. On comparing the ratios a1/a2 , b1/ and c1/c2 find out whether the following pair of linear equations are consistent , or inconsistent.
- 3x + 2y = 5 ; 2x – 3y = 7
- 2x – 3y = 8 ; 4x – 6y = 9
- 3/2x + 5/3y = 7 ; 9x – 10y = 14
- 5x – 3y = 11 ; -10x + 6y = -22
- 4/3x + 2y = 8 ; 2x + 3y = 12
Solution:-
- Hence pair of linear equation is consistent.
- Hence the pair of linear equation is inconsistent.
- Hence the pair of linear equation is consistent.
- Hence the pair of linear equation is consistent
- Hence the pair of linear equation is consistent.
Q4. Which of the following pairs of linear equation are consistent/inconsistent ? If consistent, obtain the solution graphically;
- X + y = 5 , 2x + 2y = 10
- X – y = 8 , 3x – 3y = 16
- 2x + y – 6 = 0 , 4x – 2y – 4 = 0
- 2x – 2y – 2 = 0, 4x – 4y – 5 = 0
Solution:-
- X + y = 5 ; 2x + 2y = 10
Hence the pair of linear equation is consistent.
X + y = 5
X = 5 – y
x | 4 | 3 | 2 |
y | 1 | 2 | 3 |
And , 2x + 2y = 10
X = 10 – 2y/2
x | 4 | 3 | 2 |
y | 1 | 2 | 3 |
Graphical representation
From the figure it can be observed that these lines are overlapping each other. Therefore , infinite solutions are possible for the given pair of equations.
- X – y = 8 , 3x – 3y = 16
Hence the pair of linear equation is inconsistent.
- 2x + y – 6 = 0 , 4x – 2y – 4 = 0
Hence the pair of linear equation is consistent.
2x + y – 6 = 0
Y = 6 – 2x
x | 0 | 1 | 2 |
y | 6 | 4 | 2 |
And , 4x – 2y – 4 = 0
Y = 4x – 4/2
x | 1 | 2 | 3 |
y | 0 | 2 | 4 |
Graphical representation
From the figure , it can be observed that these lines are intersecting each other at the only one point (2,2) which is the solution for the given pair of equations.
- 2x – 2y – 2 = 0 , 4x – 4y – 5 = 0
Hence the pair of linear equation is inconsistent
Q5. Half the perimeter of a rectangular garden , whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.
Solution:-
Y – x = 4 (i)
Y + x = 36 (ii)
Y – x = 4
Y = x + 4
x | 0 | 8 | 12 |
y | 4 | 12 | 16 |
Y + x = 36
x | 0 | 36 | 16 |
y | 36 | 0 | 20 |
Graphical representation
From the figure , it can be observed that these lines are intersecting each other at only point (16,20) Therefore , the length and width of the given garden is 20 m and 16 m respectively.
Q6. Given the linear equation 2x + 3y – 8 = 0 write another linear equations in two variables such that the geometrical representation of the pair so formed is:
- Intersecting lines
- Parallel lines
- Coincident lines
Solution:-
- Intersecting lines:
For this conditions
A1/a2 ≠ b1/b2
- Parallel lines
For this conditions
A1/a2 = b1/b2 ≠ c1 / c2
- Coincident lines
For coincident lines
A1/a2 = b1/b2 = c1/c2
Q7. Draw the graph of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0 . Determine the coordinates of the vertices of the triangle formed by these lines and the x – axis , and shade the triangular region.
Solution:-
X – y + 1 = 0
X = y – 1
x | 0 | 1 | 2 |
y | 1 | 2 | 3 |
3x + 2y – 12 = 0
X = 12 – 2y/3
x | 4 | 2 | 0 |
y | 0 | 3 | 6 |
Graphical representation
From the figure it can be observed that these lines are intersecting each other at point (2,3) and x – axis at (1,0) and (4,0) Therefore , the vertices of the triangle are (2,3) (-1,0) and (4,0).