NCERT Solutions For Class 9 Math Chapter – 1 Exercise – 1.2
Q1. State whether the following statements are true or false. Justify your answers.
- Every irrational number is real number.
Solution:-
True.
- Every point on the number line is of the form √m where m is a natural number.
Solution:-
False
- Every real number is a irrational number.
Solution:-
False
Q2. Are the square roots of all positive integer irrational ? If not , give an example of the square root of a number that is a rational number.
Solution:-
No , the square roots of all positive integers re not irrational.
For example,
√4 = 2 is rational.
√9 = 3 rational.
Hence , the square roots of positive integers 4 and 9 are not irrational.
Q3. Show how √5 can be represented on the number line.
Solution:-
Steps 1: Let line AB be of 2 unit on a number line.
Steps 2: At B , draw a perpendicular line BC of length 1 unit.
Steps 3: Join CA
Steps 4: Now , ABC is a right triangle Applying Pythagoras theorem
AB2 + BC2 = CA2
22 + 12 = CA2 = 5
CA = √5 Thus , CA is a line of length √5 units.
Step 5: Taking CA as a radius and A as a center draw an arc touching the number line. The point at which number line get intersected by arc is at √5 distance from 0 a because it is a radius of the circle whose center was A.
Thus √5 is represented on the number line as shown in the figure.
Q4. Classroom activity (Constructing the ‘square root spiral’) Take a large sheet of paper and construct the ‘square root spiral’ in the following fashion. Start with a point O and draw a line segment OP of unit length Draw a line segment P1P2 perpendicular to OP of unit length. Now a draw a line segment P2P3 perpendicular perpendicular to OP2. Then draw a line segment P3P4. perpendicular to OP3. Continuing in Fig 1.9:
Constructing this manner you can get the line segment Pn-1 Pn by square root spiral drawing a line segment of unit length perpendicular to OPN-1 In this manner , you will have created the points P2 , P3 ……,Pn- , ……….and joined them to a create a beautiful spiral depicting √2 , √3 , √4, …..
Solution:-
Step 1: Mark a point O on the paper Here O will be the center of the square root spiral.
Step 2: From O, draw a straight line OA , of 1 cm horizontally.
Step 3: From A , draw a perpendicular line AB of 1 cm.
Step 4: Join OB , Here, OB will be of √2.
Step 5: Now , from B , draw a perpendicular line of 1 cm and mark the end point C.
Step 6: Join OC Here , OC will be of √3
Step 7: Repeat the steps to draw √4 , √5 , √6….