NCERT Solution for Class 8 Math Chapter – 2 Exercise – 2.3
Q1. Solve the following equations and check your results.
- 3x = 2x + 18
Solution:-
3x – 2x = 18
X = 18
3 x 18 = 2 x 18 + 18
54 = 54
LHS = RHS
- 5t – 3 = 3t – 5
Solution:-
5t – 3 = 3t – 5
5t – 3t = -5 + 3
2t = -2
T = -1
-5 -3 = -3 – 5
-8 = -8
LHS = RHS
- 5x + 9 = 5 + 3x
Solution:-
5x + 9 = 5 + 3x
5x – 3x = 5 – 9
2x = -4
X = -4/2
X = -2
-10 + 9 = 5 + (-6)
-1 = -1
LHS = RHS
- 4z + 3 = 6 + 2z
Solution:-
4z – 2z = 6 -3
2z = 3
Z = 3/2
( 4 x 3/2) + 3 = 6 + ( 2 x 3/2)
= 6 + 3 = 6 + 3
= 9 = 9
LHS = RHS
- 2x – 1 = 14 – x
Solution:-
2x – 1 = 14 – x
2x + x = 14 + 1
3x = 15
X = 15/3
X = 5
10 – 1 = 9
9 = 9
LHS = RHS
- 8x + 4 = 3( x – 1) + 7
Solution:-
8x + 4 = 3( x – 1 ) + 7
8x + 4 = 3x – 3 + 7
8x – 3x = -3 -4 + 7
5x = 0
X = 0
0 + 4 = 0 – 3 + 7
4 = 4
RHS = LHS
- X = 4/5 ( x + 10)
Solution:-
X = 4/5 ( x + 10)
X = 4x/5 + 40/5
X – (4x/5) = 8
( 5x – 4x)/5 = 8
X = 8 x 5
X = 40
40 = 4/5 ( 40+10)
40 = 4/5 x 50
40 = 200/5
40 = 40
- 2x/3 + 1 = 7x/15 + 3
Solution:-
2x/3 + 1 = 7x/15 + 3
2x/3 -7x/15 = 3 – 1
= (10x – 7x)/15 = 2
3x = 2 x 15
3x = 30
X = 30/3
X = 10
2 x 10/3 + 1 = 7 x 10/15 + 3
LHS = RHS
- 2y + 5/3 = 26/3 – y
Solution:-
2y + 5/3 = 26/3 – y
= 2y + y = 26/3 – 5/3
3y = ( 26 – 5)/3
3y = 21/3
Y = 7/3
( 2 x 7/3) + 5/3 = 26/3 – 7/3
19/3 = 19/3
LHS = RHS
(X) 3M = 5M – 8/5
Solution:-
3m = 5m – 8/5
5m – 3m = 8/5
2m = 8/5
2m x 5 = 8
10m = 8 m = 10/8
M = 5/4
= 3 x (4/5) = ( 5 x 4/5) – 8/5
= 12/5 = 12/5
LHS = RHS
Also Read