NCERT Solution for Class 8th Maths Chapter – 1 Rational Numbers
Exercise – 1.1
Q1. Using appropriate properties find.
- -2/3 x 3/5 + 5/2 – 3/5 x 1/6
Solution:-
= -2/3 x 3/5 + 5/2 – 3/5 x 1/6
= -2/3 x 3/5 – 3/5 x 1/6 + 5/2 ( by commutativity)
= 3/5 ( -2/3 – 1/6 ) + 5/2
= 3/5 (( -4 -1 )/6) + 5/2
= 3/5 (( -5)/6) + 5/2 ( by distributivity)
= -15/30 + 5/2
= -1/2 + 5/2
= 4/2
= 2
- 2/5 x (-3/7) – 1/6 x 3/2 + 1/14 x 2/5
Solution:-
= 2/5 x (-3/7 + 1/4 ) – 3/12
= 2/5 x (( -6 + 1)/14) – 3/12
= 2/5 x (( -5 / 14)) – 1/4
= (-10/70) – 1/4
= -1/7 – 1/4
= (-4-7) / 28
= -11/28
Q2. Write the additive inverse of each of the following
- 2/8
= Additive inverse of 2/8 is -2/8.
- -5/9
Additive inverse of -5/9 is 5/9
- -6/-5 = 6/5
Solution:-
Additive inverse of 6/5 is -6/5
- 2/-9 = -2/9
Solution:-
Additive inverse of -2/9 is 2/9
- 19/-16 = -19/16
Solution:-
= Additive inverse of -19/16 is 19/16
Q3. Verify that (-x) = x for.
- X = 11/15
- X = -13/17
Solution:-
- X = 11/15
We have , x = 11/15
Then, the additive inverse of 11/15 is -11/15 ( as 11/15 + (-11/15) = 0)
The same equality 11/15 + (-11/15) = 0 , Show that the additive inverse of -11/15 is 11/15
Or, -(-11/15) = 11/15
- e -(-x) = x
- -13/17
Solution:-
We have , x = -13/17
The additive inverse of x is -x ( as x + (-x) = 0)
Then, the additive inverse of -13/17 is 13/17 ( as 13/17 + (-13/17)= 0 )
The same equality (-13/17 + 13/17 ) = 0, shows that the additive inverse of 13/17 is -13/17.
Or, -(13/17) = -13/17
- e -(-x) = x
Q4. Find the multiplicative inverse of the
- -13
Multiplicative inverse of -13/19 is -19/13.
- -13/19
Solution:-
= Multiplicative inverse of -13/19 is -19/13.
- 1/5
Solution:-
Multiplicative inverse of 1/5 is 5
- -5/8 x (-3/7) = 15/56
Solution:-
Multiplicative inverse of 15/56 is 56/15
- -1 x (-2/5) = 2/5
Solution:-
Multiplicative inverse of 2/5 is 5/2
- -1
Solution:-
Multiplicative inverse of -1 is -1.
Q5.Name the property under multiplication used in each of the following.
- -4/5 x 1 = 1 x (-4/5) = -4/5
Solution:-
Multiplicative identity
- -13/17 x (-2/7) = -2/7 x (-13/17)
Solution:-
Commutativity property
- -19/29 x 29/-19 = 1
Solution:-
Multiplicative inverse
Q6. Multiply 6/13 by the reciprocal of -7/16
Solution:-
Reciprocal of -7/16 = 16/-7 = -16/7
6/13 x ( Reciprocal of -7/16)
6/13 x (-16/7) = -96/91
Q7. Tell what property allows you to compute 1/3 x ( 6 x 4/3) as ( 1/3 x 6) x 4/3
Solution:-
1/3 x ( 6 x 4/3) = (1/3 x 6) x 4/3
Here, the way in which factors are grouped in a multiplication problem, supposedly does not change the product. Hence , the associativity property is used here.
Q8. Is 8/9 the multiplication inverseof -1 1/8 ? Why or why not?
Solution:-
8/9 is not the multiplicative inverse of 11/8
Q9. If 0.3 the multiplicative inverse of 31/3 ? Why or why not ?
Solution:-
31/3 = 10/3
0.3 = 3/10
3/10 x 10/3 = 1
Therefore, 0.3 is the multiplicative inverse of 31/3
Q10. Write
- The rational number that does not have a reciprocal
Solution:-
0 = 0/1
Reciprocal of 0 = 1/0 which is not defined.
- The rational numbers that are equal to their reciprocals.
Solution:-
1 = 1/1
Reciprocal of 1 = 1/1 = 1, Similarly , Reciprocal of -1 = -1
- The rational number that is equal to is negative.
Solution:-
= negative of 0 =-0=0
Q-11 Fill in the blanks :-
- Zero has ______
- The number _________ and ______ are their own reciprocals
- The reciprocal of -5 is _________
- Reciprocal of 1/x where x, ≠ 0 is _______
- The product of two rational is always a _________
- The reciprocal of a positive rational number is _________.
Solution:-
- No
- -1
- -1/5
- X
- Rational numbers
NCERT Solution for Class 7th Maths Exercise – 15.1 Chapter – 15 Visualising solid Shapes