NCERT Solutions For Class 10 Math Chapter – 3 Exercise – 3.6

NCERT Solutions For Class 10 Math Chapter – 3 Exercise – 3.6

 

Q1.  Solve the following pairs of linear equation by reducing them to a pair of linear equations:

  • 1/2x + 1/3y = 2

1/3x + 12y = 13/6

  • 2/√x + 3/√y = 2

4/x – 9/y = -1

  • 4/x + 3y = 14

3/x – 4y = 23

  • 5/x-1 + 1/y – 2 = 2

6/x- 1 – 3/y – 2 = 1

  • 7x – 2y/xy  = 5

8x + 7y /xy = 15

  • 6x + 3y = 6xy

2x + 4y = 5xy

  • 10/x + y  + 2/x – y  = 4

15/x + y  – 5/x – y   = -2

  • 1/3x
    + y    + 1/3x – y   = 3/4

1/2(3x + y)   – 1/2(3x – y)   = -1/8

Solution:-

 

  • 3a + 2b = 12 (I)

2a + 3b = 13 (ii)

Solving (I) and (ii) we get

A = 2 , b = 3

X = 1/2  , y = 1/3

 

  • 2a + 3b = 2 (I)

4a – 9b = -1 (ii)

Solving (I) and (ii) we get a = 1/2  , b = 1/3

A = 1/2 = 1/√x = 1/2

√x = 2 = x = 4

B = 1/3 = 1/√y = 1/3

√y = 3 y = 9

 

  • 4a + 3y = 14 (I)

3a – 4y = 23 (ii)

Solving for a and y we get

A = 5 y = -2

1/x = 5 and y = -2

X = 1/5  y = -2

 

  • 5a+ b = 2 (I)

6a – 3 = 1 (ii)

Solving (I)) and (ii) we get

A = 1/3  , b  = 1/3

1/x-1 = 1/3  and 1/y – 2 = 1/3

X = 4 and y = 5 is the solution,

 

  • 7/y – 2/x = 5 (I)

8/y + 7/x = 15 (ii)

 

7b – 2a = 5 (I)

8b + 7a = 15 (ii)

Solving for  a , b we get

A = 1 and b = 1

1/x = 1 and 1/y = 1

X = 1 and y = 1 is the solutions.

 

  • 6/y + 3/x = 6

2x + 4y = 5xy

2/y + 4/x = 5

Let 1/x = a , 1/y  = b.

From (I) and (ii) we get

6b + 3a = 6 (iii)

2b +  4a = 5 (iv)

Solving (iii) and (iv) we get a = 1 , b = 1/2

A = 1 = 1/x = 1 x = 1

B = 1/2 1/y = 1/2 = y= 2

 

  • 10a + 2b = 4 (I)

15a – 5b = -2 (ii)

Solving (I) and (ii) we get a = 1/5 b = 1

A = 1/5 = 1/x + y = 1/5 = x + y = 5 (iii)

B = 1 1/x-y = 1 = x – y = 1 (iv)

Solving (iii) and (iv) we get x = 3  , y = 2

 

  • 4a + 4b = 3 (I)

4a – 4b = -1 (ii)

Solving (I) and (ii) we get a = 1/4 ,  b = 1/2

A = 1/4 = 1/3x + y = 1/4

3x + y = 4 (iii)

B = 1/22 = 1/3x – y = 1/2

3x – y =  2 (iv)

Solving (iii) and (iv) we get x = 1 , y = 1.

 

Q2. Formulate the following problems as a pair of equations . and hence find their solutions:

  • Ritu can row downstream 20 km in 2 hours , and upstream 4 km in 2 hours . Find her speed of rowing in still water and the speed of the current.
  • 2 women and 5 men can together finish an embroidery work in 4 days while 3 women and 6 men can finish it in 3 days. Find the time taken by 1 women alone to finish the work, and also that taken by 1 man alone.
  • Roohi travels 300 km to her home partly by train and party by Bus She takes 4 hours if she travels 60 km by train and the remaining by bus, she takes 10 minute longer . Find the speed of the train and the bus separately.

Solution:-

 

  • x + y = 10 (I)

X – y = 2 (ii)

Solving (I) and (ii) we get x = 6 , y = 4.

 

  • 20/x + 8/y = 1 (I)

18/x + 9/y = 1

Solving for x and y we get x = 36 , y = 18

  • 15/x + 60/y = 1 (I)

4/x + 8/y = 1/6 (ii)

Multiplying (I) by 2 (ii) by 15 and then subtracting we get

 

-30/x = -3/6         15/60 + 60/y = 1

X = 60    ,             y = 80

 

 

 

NCERT Solutions For Class 10 Math Chapter – 3 Exercise – 3.6   Q1.  Solve the following pairs of linear equation…