# EXERCISE -2.6

Q1. Find:

(i) 0.2 x 6

SOLUTION:-

We have,

= (2/10) x 6

= (12/10)

On dividing a decimal  by 10,the decimal point is shifted to the left by one place .

Then,

= 1.2

(ii) 8 x 4.6

SOLUTION:-

= 36.8

(iii) 2.71 x 5

SOLUTION:-

= 13.55

(iv) 20.1 x 4

SOLUTION:-

= 80.4

(v) 0.05 x 7

SOLUTION:-

= 0.35

(vi) 211.02 x 4

SOLUTION:-

= 844.08

(vii) 2 x 0.86

SOLUTION:-

= 1.72

Q2. Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.

SOLUTION:-

Area of rectangle = 2(l + b)

= 2 x 8.7

= 17.4 cm2.

Q3. Find:

(i) 1.3 x 10

SOLUTION:-

= 13

(ii) 36.8 x 10

SOLUTION:-

= 368

(iii)

153.7 x 10

SOLUTION:-

= 1537

(iv) 168.07 x 10

SOLUTION:-

= 1680.70

(v)  31.1 x 100

SOLUTION:-

= 3110

(vi) 156.1 x 100

SOLUTION:-

= 15610

(vii) 3.62 x 100

SOLUTION:-

= 362

(viii) 43.07 x 100

SOLUTION:-

= 4307

(ix) 0.5 x 10

SOLUTION:-

= 5

(x) 0.08 x 10

SOLUTION:-

= 0.8

(xi) 0.9 x 100

SOLUTION:-

= 90

(xii) 0.03 x 1000

SOLUTION:-

= 30

Q4. A two wheeler covers a distance of 55.3 km in one liter petrol . How much distance will it cover in 10 liters of petrol ?

SOLUTION:-

From the question, it is given that ,

Distance covered by two wheeler in 1 liter petrol = 55.3 km

Then,

Distance covered by two wheeler in 10 liters petrol = ( 10 x 55.3)

= 553 km

Two wheeler covers a distance in 10 liters petrol  is 553 km.

Q5. Find:

(i) 2.5 x 0.3

SOLUTION:-

= 0.75

(ii) 0.1 x 51.7

SOLUTION:-

= 5.17

(iii) 0.2 x 316.8

SOLUTION:-

= 63.36

(iv) 1.3 x 3.1

SOLUTION:-

= 4.03

(v) 0.5 x 0.05

SOLUTION:-

= 0.025

(vi) 11.2 x 0.15

SOLUTION:-

= 1.68

(vii) 1.07 x 0.02

SOLUTION:-

= 0.0214

(viii) 10.05 x 1.05

SOLUTION:-

= 10.5525

(ix) 101.01 x 0.01

SOLUTION:-

= 1.0101

(x) 100.01 x 1.1

SOLUTION:-

= 110.011